An object of mass 0.2 kg executes simple harmonic motion along x axis with frequency of ( 25 )Hz. At the position x = 0.04 m the object has kinetic energy 0.5 J and potential energy 0.4 J. The amplitude of oscillation is cm.
6
= 2 f = 2 25 = 50 rad/s
Total energy E = K + U = 0.5 + 0.4 = 0.9 J
E = 12m 2A2
0.9 = 12 0.2 2500 A2 = 250A2
A2 = 0.0036 A = 0.06 m = 6 cm
Answer: 6
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