A particle is projected at an angle of 30 from horizontal at a speed of 60 m/s. The height traversed by the particle in the first second is h0 and height traversed in the last second, before it reaches the maximum height, is h1. The ratio h0:h1 is . [Take, g=10 m/s2 ]
Answer
5
Solution
Only the vertical motion matters: uy=60 30 =30 m/s, top reached at t=3 s.
[figure]
First second: h0=30 1- 12 10 12=25 m
Last second before the top = first second of a free fall from rest: h1= 12 10 12=5 m
h0:h1=5
Answer: 5