For three vectors A = (-x i - 6 j - 2 k), B = (- i + 4 j + 3 k) and C = (-8 i - j + 3 k), if A ( B C) = 0, then value of x is .
Answer
4
Solution
A ( B C) = vmatrix -x & -6 & -2 \ -1 & 4 & 3 \ -8 & -1 & 3 vmatrix = 0
-x(12 + 3) + 6(-3 + 24) - 2(1 + 32) = 0
-15x + 126 - 66 = 0
x = 4
Answer: 4