A ball of mass 100 g is projected with velocity 20 m/s at 60 with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is
- 20 J
- 5 J
- 15 J
- zero
Answer
(3) 15 J
Solution
[figure]
At the highest point only u 60 =10 m/s remains
Ki= 12(0.1)(20)2=20 J, Kf= 12(0.1)(10)2=5 J
K=20-5=15 J
Answer: (3)