Three bodies A, B and C have equal kinetic energies and their masses are 400 g, 1.2 kg and 1.6 kg respectively. The ratio of their linear momenta is :
- 1 : 3 : 2
- 3 : 2 : 1
- 1 : 3 : 2
- 2 : 3 : 1
Answer
(1) 1 : 3 : 2
Solution
p = 2mK; K same ⇒ p m
pA : pB : pC = 0.4 : 1.2 : 1.6
= 1 : 3 : 4 = 1 : 3 : 2
Answer: (1)