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Some Basic Concepts of Chemistry

AIPMT 2004MCQEasy📈 Topic in 50% papers+4−1
Ques. 1AIPMT 2004

The maximum number of molecules is present in

  1. 15 L of H2 gas at STP
  2. 5 L of N2 gas at STP
  3. 0.5 g of H2 gas
  4. 10 g of O2 gas

Answer

(1) 15 L of H2 gas at STP

Solution

Number of molecules ∝ number of moles. At STP, 1 mol of gas occupies 22.4 L.

(1) n = 1522.4 = 0.67 mol

(2) n = 522.4 = 0.22 mol

(3) n = 0.52 = 0.25 mol

(4) n = 1032 = 0.31 mol

∴ 15 L of H2 at STP has the maximum number of moles and hence of molecules.

Answer: (1)

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Ques. 2AIPMT 2003

In Haber process 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?

  1. 20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
  2. 10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
  3. 20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen
  4. 20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
Out of syllabus
Ques. 3AIPMT 2002

Which has maximum molecules?

  1. 7 g N2
  2. 2 g H2
  3. 16 g NO2
  4. 16 g O2
Ques. 4AIPMT 2002

The percentage of C, H and N in an organic compound are 40%, 13.3% and 46.7% respectively then empirical formula is

  1. C3H13N3
  2. CH2N
  3. CH4N
  4. CH6N
Ques. 5AIPMT 2002

2.5 litre of 1 M NaOH solution is mixed with another 3 litre of 0.5 M NaOH solution. Then find out molarity of resultant solution.

  1. 0.80 M
  2. 1.0 M
  3. 0.73 M
  4. 0.50 M
Ques. 6AIPMT 2001

Percentage of Se in peroxidase anhydrous enzyme is 0.5\% by weight (at. wt. = 78.4), then the minimum molecular weight of peroxidase anhydrous enzyme is

  1. 1.568 104
  2. 1.568 103
  3. 15.68
  4. 2.136 104
Ques. 7AIPMT 2001

Molarity of liquid HCl, if density of solution is 1.17 g/cc, is

  1. 36.5
  2. 18.25
  3. 32.05
  4. 42.10
Ques. 8AIPMT 2001

Specific volume of cylindrical virus particle is 6.02 10-2 cc/g whose radius and length are 7 A and 10 A respectively. If NA = 6.02 1023, find molecular weight of virus.

  1. 15.4 kg/mol
  2. 1.54 104 kg/mol
  3. 3.08 104 kg/mol
  4. 3.08 103 kg/mol
Ques. 9AIPMT 2000

Volume of CO2 obtained by the complete decomposition of 9.85 g of BaCO3 is

  1. 2.24 L
  2. 1.118 L
  3. 0.84 L
  4. 0.56 L

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