The percentage of C, H and N in an organic compound are 40%, 13.3% and 46.7% respectively then empirical formula is
(3) CH4N
Taking 100 g of the compound, the moles of each element are:
C: 4012 = 3.33
H: 13.31 = 13.3
N: 46.714 = 3.33
Dividing by the smallest value (3.33) gives C : H : N = 1 : 4 : 1.
∴ Empirical formula = CH4N
Answer: (3)
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