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Laws of Motion

JEE Main 2025 (Online) 24th January Morning ShiftMCQMedium📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2025, 24 January (Morning Shift)

A car of mass 'm' moves on a banked road having radius 'r' and banking angle . To avoid slipping from banked road, the maximum permissible speed of the car is v0. The coefficient of friction between the wheels of the car and the banked road is

  1. = v02+rg rg+v02
  2. = v02-rg rg-v02
  3. = v02-rg rg+v02
  4. = v02+rg rg-v02

Answer

(3) = v02-rg rg+v02

Solution

At maximum speed the car tends to slide up, so friction N acts down the slope.

[figure]

N - N =mg, N + N = mv02r

v02rg= + 1-

= v02-rg rg+v02

Answer: (3)

Keep practising — Laws of Motion

Ques. 2JEE Main 2025, 24 January (Evening Shift)

[figure] A string of length L is fixed at one end and carries a mass of M at the other end. The mass makes ( 3 ) rotations per second about the vertical axis passing through end of the string as shown. The tension in the string is ML.

Ques. 3JEE Main 2025, 22 January (Evening Shift)

A tube of length 1 m is filled completely with an ideal liquid of mass 2M, and closed at both ends. The tube is rotated uniformly in horizontal plane about one of its ends. If the force exerted by the liquid at the other end is F then angular velocity of the tube is F M in SI unit. The value of is .

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