Light ray incident along a vector AO ( AO=2 i-3 j ) emerges out along vector OB ( OB=C i-4 j ) as shown in the figure below. The value of C is . [figure]
- 1.6
- 0.16
- 11.6
- 16
Answer
(1) 1.6
Solution
[figure]
The normal at O is along the y-axis, and the angles and are measured from it.
AO = 2 i - 3 j, = 2 22 + 32 = 2 13; and OB = C i - 4 j, = C C2 + 16.
By Snell's law, 1 = 2 :
1 2 13 = 1.5 C C2 + 16
Squaring, 413 = 2.25 C2C2 + 16
4C2 + 64 = 29.25 C2
C2 = 6425.25 2.53
C 1.6
Answer: (1)