A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is : [figure]
- -
- - 2
- -45
- +45
Answer
(3) -45
Solution
Using the lens formula 1v - 1u = 1f with f = +20 cm:
For point A (on axis), u = −30 cm, so 1vA = 120 - 130 = 160 and vA = 60 cm (on the axis).
For point B, u = −29 cm and height h = 2 cm, so 1vB = 120 - 129 = 9580 and vB = 5809 cm.
Its magnification is m = vBu = 580/9-29 = - 209, so h' = mh = - 409 cm.
The horizontal extent of the image is vB - vA = 5809 - 5409 = 409 cm, hence
= h'vB - vA = -40/940/9 = -1
= -45 (image inverted, sloping below the axis)
Answer: (3)