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Semiconductor Electronics

JEE Main 2024 (Online) 30th January Evening ShiftMCQEasy📈 Topic in 19% papers+4−1
Ques. 1JEE Main 2024, 30 January (Evening Shift)

[figure] In the given circuit, the voltage across load resistance (RL) is :

  1. 8.75 V
  2. 9.00 V
  3. 8.50 V
  4. 14.00 V

Answer

(1) 8.75 V

Solution

Both diodes are forward biased; drop across Ge = 0.3 V, across Si = 0.7 V.

i= 15-0.3-0.7(1.5+2.5) k = 14 V4 k =3.5 mA

VL=iRL=3.5 mA 2.5 k =8.75 V

Answer: (1)

Keep practising — Semiconductor Electronics

Ques. 2JEE Main 2024, 29 January (Morning Shift)

In the given circuit, the breakdown voltage of the Zener diode is 3.0 V. What is the value of Iz ? [figure]

  1. 3.3 mA
  2. 10 mA
  3. 5.5 mA
  4. 7 mA
Ques. 3JEE Main 2024, 29 January (Evening Shift)

The truth table for this given circuit is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2024, 27 January (Morning Shift)

Which of the following circuits is reverse - biased?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 5JEE Main 2024, 27 January (Evening Shift)

The truth table of the given circuit diagram is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

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