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Semiconductor Electronics

JEE Main 2024 (Online) 29th January Morning ShiftMCQEasy📈 Topic in 26% papers+4−1
Ques. 1JEE Main 2024, 29 January (Morning Shift)

In the given circuit, the breakdown voltage of the Zener diode is 3.0 V. What is the value of Iz ? [figure]

  1. 3.3 mA
  2. 10 mA
  3. 5.5 mA
  4. 7 mA

Answer

(3) 5.5 mA

Solution

[figure]

Zener in breakdown ⇒ VAB=VCD=3 V

I= 10-31 k =7 mA, IL= 32 k =1.5 mA

I=Iz+IL (junction rule at A)

Iz=7-1.5=5.5 mA

Answer: (3)

Keep practising — Semiconductor Electronics

Ques. 2JEE Main 2024, 29 January (Evening Shift)

The truth table for this given circuit is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 3JEE Main 2024, 27 January (Morning Shift)

Which of the following circuits is reverse - biased?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2024, 27 January (Evening Shift)

The truth table of the given circuit diagram is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

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