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Units and Measurements

JEE Main 2025 (Online) 23rd January Evening ShiftMCQMedium📈 Topic in 33% papers+4−1
Ques. 1JEE Main 2025, 23 January (Evening Shift)

The energy of a system is given as E(t)= 3e- t, where t is the time and =0.3 s-1. The errors in the measurement of and t are 1.2\% and 1.6\%, respectively. At t=5 s, maximum percentage error in the energy is :

  1. 6\%
  2. 11.6\%
  3. 4\%
  4. 8.4\%

Answer

(1) 6\%

Solution

E=3 - t EE=3 + t

t=1.6\% of 5 s=0.08 s

EE=3(0.012)+0.3(0.08)=0.036+0.024=0.06

Maximum error = 6\%

Answer: (1)

Keep practising — Units and Measurements

Ques. 2JEE Main 2025, 23 January (Evening Shift)

Match List - I with List - II Choose the correct answer from the options given below :

  1. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  2. (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  3. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  4. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Ques. 3JEE Main 2025, 22 January (Morning Shift)

If B is magnetic field and 0 is permeability of free space, then the dimensions of (B/ 0) is

  1. MT-2A-1
  2. L-1A
  3. ML2T-2A-1
  4. LT-2A-1
Ques. 4JEE Main 2025, 22 January (Morning Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below.

  1. Both Statement I and Statement II are false
  2. Statement I is true but Statement II is false
  3. Both Statement I and Statement II are true
  4. Statement I is false but Statement II is true
Ques. 5JEE Main 2025, 22 January (Evening Shift)

Which one of the following is the correct dimensional formula for the capacitance in F ? M, L, T and C stand for unit of mass, length, time and charge respectively.

  1. [F]= [ C M-1L-2T2 ]
  2. [F]= [ C2M-2L2T2 ]
  3. [F]= [ C2M-1L-2T2 ]
  4. [F]= [ C M-2L-2T-2 ]
Ques. 6JEE Main 2025, 22 January (Evening Shift)

The maximum percentage error in the measurement of density of a wire is [Given, mass of wire =(0.60 0.003) g radius of wire =(0.50 0.01) cm length of wire =(10.00 0.05) cm]

  1. 7
  2. 8
  3. 5
  4. 4
Ques. 7JEE Main 2024, 9 April (Morning Shift)

The dimensional formula of latent heat is :

  1. [ M0LT-2]
  2. [ MLT-2]
  3. [ M0L2T-2]
  4. [ ML2T-2]
Ques. 8JEE Main 2024, 9 April (Morning Shift)

One main scale division of a vernier caliper is equal to m units. If nth division of main scale coincides with (n + 1)th division of vernier scale, the least count of the vernier caliper is :

  1. 1(n + 1)
  2. m(n + 1)
  3. n(n + 1)
  4. mn(n + 1)
Ques. 9JEE Main 2024, 9 April (Evening Shift)

The de-Broglie wavelength associated with a particle of mass m and energy E is h/ 2mE. The dimensional formula for Planck's constant is :

  1. [ M2 L2 T-2 ]
  2. [ ML-1 T-2 ]
  3. [ ML2 T-1 ]
  4. [ MLT-2 ]
Ques. 10JEE Main 2024, 8 April (Morning Shift)

In an expression a 10b :

  1. a is order of magnitude for b 5
  2. b is order of magnitude for a 5
  3. b is order of magnitude for a 5
  4. b is order of magnitude for 5 < a 10
Ques. 11JEE Main 2024, 8 April (Morning Shift)

Young's modulus is determined by the equation given by Y = 49000 Ml dynecm2 where M is the mass and l is the extension of wire used in the experiment. Now error in Young modulus (Y) is estimated by taking data from M–l plot in graph paper. The smallest scale divisions are 5 g and 0.02 cm along load axis and extension axis respectively. If the value of M and l are 500 g and 2 cm respectively then percentage error of Y is :

  1. 2%
  2. 0.02%
  3. 0.5%
  4. 0.2%

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