The de-Broglie wavelength associated with a particle of mass m and energy E is h/ 2mE. The dimensional formula for Planck's constant is :
- [ M2 L2 T-2 ]
- [ ML-1 T-2 ]
- [ ML2 T-1 ]
- [ MLT-2 ]
Answer
(3) [ ML2 T-1 ]
Solution
= h 2mE, so h = 2mE, where 2mE is the momentum p (the number 2 has no dimensions).
[h] = [ ][p] = L MLT-1
= [ ML2T-1 ]
Answer: (3)