p-Block Elements (Group 15–18)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

1. Statement I is false but Statement II is true
2. Both Statement I and Statement II are true
3. Both Statement I and Statement II are false
4. Statement I is true but Statement II is false

The property/properties that show irregularity in first four elements of group-17 is/are Choose the correct answer from the options given below :

1. A, B, C and D
2. A and C only
3. B only
4. B and D only

The nature of oxide (TeO2) and hydride (TeH2) formed by Te, respectively are:

1. Reducing and basic
2. Reducing and acidic
3. Oxidising and acidic
4. Oxidising and basic

A group 15 element forms d - d bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form d - d bond. The atomic number of the element is .

The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of

1. Atomicity
2. Electron gain enthalpy
3. Atomic size
4. Electronegativity

The incorrect statement among the following is

1. PH3 shows lower proton affinity than NH3.
2. SO2 can act as an oxidizing agent, but not as a reducing agent.
3. NO2 can dimerise easily.
4. PF3 exists but NF5 does not.

The maximum covalency of a non-metallic group 15 element ' E ' with weakest E-E bond is :

1. 5
2. 3
3. 4
4. 6