Consider the following reactions : NaCl + K2Cr2O7 + H2SO4 A + KHSO4 + NaHSO4 + H2O A + NaOH B + NaCl + H2O B + H2SO4 + H2O2 C + Na2SO4 + H2O In the product 'C', 'X' is the number of O22- units, 'Y' is the total number of oxygen atoms present and 'Z' is the oxidation state of Cr. The value of X + Y + Z is .
Answer
13
Solution
The first step is the chromyl chloride test:
4NaCl + K2Cr2O7 + 6H2SO4 2CrO2Cl2 + 2KHSO4 + 4NaHSO4 + 3H2O
so A = CrO2Cl2 (chromyl chloride). With NaOH it gives yellow sodium chromate, so B = Na2CrO4:
CrO2Cl2 + 4NaOH Na2CrO4 + 2NaCl + 2H2O
Acidified H2O2 then gives the blue chromium peroxide, so C = CrO5:
Na2CrO4 + H2SO4 + 2H2O2 CrO5 + Na2SO4 + 3H2O
CrO5 has a butterfly structure with one Cr=O and two peroxo O22- groups, so X = 2 and Y = 5.
Oxidation state of Cr: Z + (−2) + 2(−2) = 0 Z = +6
X + Y + Z = 2 + 5 + 6 = 13
Answer: 13