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Chemical Bonding and Molecular Structure

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 34% papers+4−1
Ques. 1JEE Main 2025, 2 April (Morning Shift)

A molecule with the formula AX4Y has all its elements from p-block. Element A is rarest, monoatomic, non-radioactive from its group and has the lowest ionization enthalpy value among A, X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is:

  1. Pentagonal planar
  2. Square pyramidal
  3. Trigonal bipyramidal
  4. Octahedral

Answer

(2) Square pyramidal

Solution

A: monoatomic, rarest non-radioactive element of its group (group 18) with the lowest ionisation enthalpy A = Xe

X = F (highest electronegativity), Y = O (second highest)

Molecule = XeOF4

Valence electrons of Xe = 8; 4 bond pairs to F, Xe=O counts as one σ bond pair (π bond not counted)

5 bond pairs + 1 lone pair = 6 electron pairs sp3d2, octahedral arrangement

With one lone pair, the shape is square pyramidal.

Answer: (2)

Keep practising — Chemical Bonding and Molecular Structure

Ques. 2JEE Main 2025, 2 April (Morning Shift)

Among SO2, NF3, NH3, XeF2, ClF3 and SF4, the hybridization of the molecule with nonzero dipole moment and highest number of lone-pairs of electrons on the central atom is

  1. sp3
  2. dsp2
  3. sp3d2
  4. sp3d
Ques. 3JEE Main 2025, 2 April (Evening Shift)

Which among the following molecules is (a) involved in sp3d hybridization, (b) has different bond lengths and (c) has lone pair of electrons on the central atom?

  1. XeF4
  2. XeF2
  3. PF5
  4. SF4
Ques. 4JEE Main 2025, 29 January (Morning Shift)

An element 'E' has the ionisation enthalpy value of 374 kJ mol-1. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of −328, −349, −325 and −295 kJ mol-1, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :

  1. EB > EA > EC > ED
  2. EA > EB > EC > ED
  3. ED > EC > EA > EB
  4. ED > EC > EB > EA
Ques. 5JEE Main 2025, 29 January (Morning Shift)

The sum of sigma ( ) and pi ( ) bonds in Hex-1,3-dien-5-yne is .

Ques. 6JEE Main 2025, 29 January (Evening Shift)

Total number of non-bonded electrons present in NO2- ion based on Lewis theory is .

Ques. 7JEE Main 2025, 28 January (Morning Shift)

The molecules having square pyramidal geometry are

  1. BrF5 & PCl5
  2. SbF5 & PCl5
  3. BrF5 & XeOF4
  4. SbF5 & XeOF4
Ques. 8JEE Main 2025, 28 January (Evening Shift)

Total number of molecules/species from the following which will be paramagnetic is . O2, O2+, O2-, NO, NO2, CO, K2[NiCl4], [Co(NH3)6]Cl3, K2[Ni(CN)4]

Ques. 9JEE Main 2025, 24 January (Morning Shift)

Which of the following linear combination of atomic orbitals will lead to formation of molecular orbitals in homonuclear diatomic molecules [internuclear axis in z-direction] ? Choose the correct answer from the options given below:

  1. D Only
  2. E Only
  3. C and D Only
  4. A and B Only
Ques. 10JEE Main 2025, 24 January (Morning Shift)

Which of the following statement is true with respect to H2O, NH3 and CH4 ? Choose the correct answer from the options given below:

  1. A, D and E Only
  2. C, D and E Only
  3. A, B and C Only
  4. A, B, C and E Only
Ques. 11JEE Main 2025, 24 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are false

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