Let E: x2a2+ y2b2=1, a>b and H: x2A2- y2B2=1. Let the distance between the foci of E and the foci of H be 2 3. If a-A=2, and the ratio of the eccentricities of E and H is 13, then the sum of the lengths of their latus rectums is equal to :
- 10
- 7
- 9
- 8
Answer
(4) 8
Solution
Same foci ( 3,0): ae=Ae'= 3; ee'= Aa= 13 a=3A, and a-A=2 A=1, a=3
[figure]
Ellipse: b2=a2-3=6; hyperbola: B2=3-A2=2
Latus rectum: 2b2a=4 and 2B2A=4 (the same chord through F2)
Sum =8
Answer: (4)