Consider the circle C : x2+y2-6x-8y-11=0. Let a variable chord AB of the circle C subtend a right angle at the origin. If the locus of the foot of the perpendicular drawn from the origin on the chord AB is the circle x2+y2- x- y- =0, then + +2 is equal to .
Answer
18
Solution
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Let M(h, k) be the foot of the perpendicular from O on AB, so OM AB and
AB: hx + ky = h2 + k2 = p (say)
Homogenising C with hx + kyp = 1 gives the pair of lines OA, OB:
x2 + y2 - (6x + 8y) hx + kyp - 11 (hx + ky)2p2 = 0
= 90 , coefficient of x2 + coefficient of y2 = 0:
(1 - 6hp - 11h2p2 ) + (1 - 8kp - 11k2p2 ) = 0
2 - 6h + 8kp - 11p = 0 ( h2 + k2 = p )
2 (h2 + k2 ) - 6h - 8k - 11 = 0 h2 + k2 - 3h - 4k - 112 = 0
∴ = 3, = 4, = 112 and + + 2 = 3 + 4 + 11 = 18
Answer: 18