Let the centre of the circle x2+y2+2gx+2fy+25=0 be in the first quadrant and lie on the line 2x-y=4. Let the area of an equilateral triangle inscribed in the circle be 27 3. Then the square of the length of the chord of the circle on the line x=1 is .
Answer
80
Solution
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The centre C(-g, -f) = (h, k) lies on 2x - y = 4, so k = 2h - 4, and r2 = g2 + f2 - 25 = h2 + k2 - 25.
An equilateral triangle inscribed in a circle of radius r has side 3r, so
area = 34 (3r2 ) = 3 34r2 = 27 3 r2 = 36
h2 + (2h - 4)2 - 25 = 36 5h2 - 16h - 45 = 0
(h - 5)(5h + 9) = 0
The centre is in the first quadrant, so h = 5, k = 6, giving C(5, 6) and r = 6.
The distance of C from the line x = 1 is CM = 4, so the half chord is
AM = r2 - CM2 = 36 - 16 = 20
AB2 = (2 20 )2 = 80
Answer: 80