The eccentricity of an ellipse E with centre at the origin O is 32 and its directrices are x= 4 63. Let H: x2a2- y2b2=1 be a hyperbola whose eccentricity is equal to the length of semi-major axis of E, and whose length of latus rectum is equal to the length of minor axis of E. Then the distance between the foci of H is :
- 4 2 7
- 4 27
- 4 7
- 87
Answer
(4) 87
Solution
The directrices are x = constant, so the major axis of E is along the x-axis, with e = 32.
Ae = 4 63
A = 4 63 32 = 2 2 (semi-major axis)
B2 = A2 (1 - e2 ) = 8 14 = 2, so the minor axis is 2B = 2 2.
For the hyperbola H, eH = A = 2 2, so
1 + b2a2 = 8
b2 = 7a2
Its latus rectum is 2b2a = 2 2, hence
14a2a = 2 2
a = 27
∴ Distance between the foci = 2aeH = 2 27 2 2 = 87
Answer: (4)