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Semiconductor Electronics

JEE Main 2025 (Online) 7th April Morning ShiftMCQEasy📈 Topic in 21% papers+4−1
Ques. 1JEE Main 2025, 7 April (Morning Shift)

In the following circuit, the reading of the ammeter will be (Take Zener breakdown voltage = 4 V) [figure]

  1. 60 mA
  2. 80 mA
  3. 10 mA
  4. 24 mA

Answer

(3) 10 mA

Solution

The Zener diode's cathode is connected to the positive terminal side of the 12 V source, so it is reverse biased.

∵ The voltage available (12 V) is more than the breakdown voltage, the Zener conducts and holds the voltage across it at 4 V.

The 400 resistor (with the ammeter) is in parallel with the Zener:

V400 = 4 V

⇒ I = 4400 A = 0.01 A = 10 mA

(Check: current through 100 = 12 - 4100 = 80 mA > 10 mA, so the Zener carries 70 mA and stays in breakdown.)

Answer: (3)

Keep practising — Semiconductor Electronics

Ques. 2JEE Main 2025, 7 April (Evening Shift)

Consider the following logic circuit. [figure] The output is Y = 0 when :

  1. A = 1 and B = 0
  2. A = 0 and B = 0
  3. A = 1 and B = 1
  4. A = 0 and B = 1
Ques. 3JEE Main 2025, 4 April (Morning Shift)

The Boolean expression Y = A BC + A C can be realised with which of the following gate configurations. Choose the correct answer from the options given below:

  1. B, C Only
  2. A, B, C Only
  3. A, B Only
  4. A, C Only
Ques. 4JEE Main 2025, 4 April (Evening Shift)

Consider an n-type semiconductor in which ne and nh are number of electrons and holes, respectively. Choose the correct answer from the options given below :

  1. (A), (B), (E) only
  2. (A), (C), (E) only
  3. (A), (B), (C) only
  4. (A), (C), (D) only
Ques. 5JEE Main 2025, 3 April (Morning Shift)

Choose the correct logic circuit for the given truth table having inputs A and B. [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 6JEE Main 2025, 3 April (Evening Shift)

The truth table corresponding to the circuit given below is: [figure]

  1. arrayccc A & B & C \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 1 array
  2. arrayccc A & B & C \ 0 & 0 & 1 \ 1 & 0 & 0 \ 0 & 1 & 0 \ 1 & 1 & 0 array
  3. arrayccc A & B & C \ 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \ 1 & 1 & 0 array
  4. arrayccc A & B & C \ 0 & 0 & 0 \ 1 & 0 & 0 \ 0 & 1 & 0 \ 1 & 1 & 1 array
Ques. 7JEE Main 2025, 2 April (Morning Shift)

A zener diode with 5 V zener voltage is used to regulate an unregulated dc voltage input of 25 V. For a 400 resistor connected in series, the zener current is found to be 4 times load current. The load current (IL) and load resistance (RL) are :

  1. IL = 0.02 mA; RL = 250
  2. IL = 10 A; RL = 0.5
  3. IL = 10 mA; RL = 500
  4. IL = 20 mA; RL = 250
Ques. 8JEE Main 2025, 2 April (Evening Shift)

In the digital circuit shown in the figure, for the given inputs the P and Q values are : [figure]

  1. P = 0, Q = 1
  2. P = 1, Q = 0
  3. P = 0, Q = 0
  4. P = 1, Q = 1
Ques. 9JEE Main 2025, 29 January (Morning Shift)

[figure] For the circuit shown above, equivalent GATE is :

  1. NOT gate
  2. NAND gate
  3. AND gate
  4. OR gate
Ques. 10JEE Main 2025, 29 January (Evening Shift)

The truth table for the circuit given below is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 11JEE Main 2025, 28 January (Morning Shift)

Which of the following circuits has the same output as that of the given circuit? [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

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