A solid sphere (A) of mass 5m and a spherical shell (B) of mass m, both having same radius, are placed on a rough surface. When a force of same magnitude is applied tangentially at the highest points of A and B, they start rolling without slipping with an acceleration of aA and aB, respectively. The ratio of aA and aB is .
- 5 : 21
- 6 : 10
- 21 : 25
- 1 : 5
Answer
(1) 5 : 21
Solution
[figure]
Let friction f act forward at the contact point. For rolling without slipping, a = R.
Translation: F + f = Ma ...(i)
Rotation about the centre: (F - f)R = I = IRa, so F - f = IR2a ...(ii)
Adding (i) and (ii),
2F = (M + IR2 )a
a = 2FM + I/R2
For the solid sphere A (M = 5m, I = 25MR2), IR2 = 2m, so
aA = 2F5m + 2m = 2F7m
For the spherical shell B (M = m, I = 23mR2), IR2 = 23m, so
aB = 2Fm + 23m = 6F5m
∴ aAaB = 2F7m 5m6F = 521
Answer: (1)