Standard entropies of X2, Y2 and XY5 are 70, 50 and 110 J K-1 mol-1 respectively. The temperature in Kelvin at which the reaction 12X2 + 52Y2 XY5 H = -35 kJ mol-1 will be at equilibrium is (Nearest integer)
Answer
700
Solution
At equilibrium G =0 T= H S
S =110- ( 12 70+ 52 50 )=110-160=-50 J K-1 mol-1
T= -35000-50=700 K
Answer: 700