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Relations and Functions

JEE Main 2025 (Online) 29th January Evening ShiftMCQEasy📈 Topic in 13% papers+4−1
Ques. 1JEE Main 2025, 29 January (Evening Shift)

Let S = N \0\. Define a relation R from S to R by : R = \(x, y) : e y = x e ( 25 ), x S, y R \. Then, the sum of all the elements in the range of R is equal to :

  1. 32
  2. 109
  3. 52
  4. 53

Answer

(4) 53

Solution

e y=x e 25 ⇒ y= ( 25 )x, x=0,1,2,

Range =1, 25, 425, — an infinite G.P. with a=1, r= 25

∴ Sum = a1-r= 13/5= 53

Answer: (4)

Keep practising — Relations and Functions

Ques. 2JEE Main 2025, 29 January (Evening Shift)

If the domain of the function 5(18x - x2 - 77) is ( , ) and the domain of the function (x-1) ( 2x2 + 3x - 2x2 - 3x - 4 ) is ( , ), then 2 + 2 + 2 is equal to:

  1. 186
  2. 179
  3. 195
  4. 174
Ques. 3JEE Main 2025, 28 January (Morning Shift)

Let f : R R be a function defined by f(x) = (2 + 3a)x2 + ( a+2a-1 )x + b, a 1. If f(x + y) = f(x) + f(y) + 1 - 27xy, then the value of 28 i=15|f(i)| is

  1. 735
  2. 675
  3. 715
  4. 545
Ques. 4JEE Main 2025, 24 January (Evening Shift)

The number of real solution(s) of the equation x2+3x+2= \|x-3|,|x+2|\ is :

  1. 2
  2. 3
  3. 1
  4. 0
Ques. 5JEE Main 2025, 23 January (Morning Shift)

Let f(x)= e x and g(x)= x4-2x3+3x2-2x+22x2-2x+1. Then the domain of f g is

  1. (0, )
  2. [1, )
  3. R
  4. [0, )
Ques. 6JEE Main 2025, 22 January (Morning Shift)

The product of all solutions of the equation e5( ex)2+3=x8, x>0, is :

  1. e2
  2. e
  3. e6/5
  4. e8/5

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