The number of real solution(s) of the equation x2+3x+2= \|x-3|,|x+2|\ is :
(1) 2
\|x-3|,|x+2|\=|x+2| for x< 12 and |x-3| for x 12.
[figure]
x< 12: (x+1)(x+2)=|x+2| x=-2 or x+1= 1 x=-2, 0
x 12: the parabola ( 3.75) stays above |x-3| ( 2.5) no root
real solutions: x=-2, 0 — 2 solutions
Answer: (1)
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