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Relations and Functions

JEE Main 2025 (Online) 23rd January Morning ShiftMCQMedium📈 Topic in 34% papers+4−1
Ques. 1JEE Main 2025, 23 January (Morning Shift)

Let f(x)= e x and g(x)= x4-2x3+3x2-2x+22x2-2x+1. Then the domain of f g is

  1. (0, )
  2. [1, )
  3. R
  4. [0, )

Answer

(3) R

Solution

f g= g(x) needs g(x)>0.

Numerator = (x2-x+1 )2+1 1>0

Denominator =2 (x- 12 )2+ 12>0

g(x)>0 for every real x domain = R

Answer: (3)

Keep practising — Relations and Functions

Ques. 2JEE Main 2025, 22 January (Morning Shift)

The product of all solutions of the equation e5( ex)2+3=x8, x>0, is :

  1. e2
  2. e
  3. e6/5
  4. e8/5

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