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Continuity and Differentiability

JEE Main 2026 (Online) 4th April Evening ShiftNumericalMedium📈 Topic in 18% papers+4
Ques. 1JEE Main 2026, 4 April (Evening Shift)

Let f(x)= casesex-1, & x<0\ x2-5x+6, & x 0 cases and g(x)=f(|x|)+|f(x)|. If the number of points where g is not continuous and is not differentiable are and respectively, then + is equal to .

Answer

4

Solution

f(|x|)=|x|2-5|x|+6=x2-5|x|+6 for all x ( |x| 0)

For x<0: g(x)=x2+5x+6+ex-1

For x 0: g(x)= (x2-5x+6 )+ |x2-5x+6 |= cases2(x-2)(x-3), & 0 x 2\ 0, & 2<x<3\ 2(x-2)(x-3), & x 3 cases

Continuity at x=0: g(0-)=6+e-1, g(0)=12 discontinuous

Everywhere else g is continuous =1

Differentiability: not differentiable at x=0 (discontinuous).

At x=2: g'(2-)=2(2x-5) |x=2=-2, g'(2+)=0 not differentiable

At x=3: g'(3-)=0, g'(3+)=2(2x-5) |x=3=2 not differentiable

=3 (at x=0, 2, 3)

+ =1+3=4

Answer: 4

Keep practising — Continuity and Differentiability

Ques. 2JEE Main 2026, 2 April (Evening Shift)

The number of points in the interval [2, 4], at which the function f(x)= [x2-x- 12 ], where [ ] denotes the greatest integer function, is discontinuous, is .

Ques. 3JEE Main 2026, 28 January (Evening Shift)

Let f(x) = 0 ( x - x ( 2 ) (x - 1)1 + x ( 2 )(x - 1) ), x R. Consider the following two statements : (I) f(x) is discontinuous at x = 1. (II) f(x) is continuous at x = -1. Then,

  1. Neither (I) nor (II) is True
  2. Only (II) is True
  3. Only (I) is True
  4. Both (I) and (II) are True
Ques. 4JEE Main 2026, 24 January (Morning Shift)

Let , R be such that the function f(x) = cases 2 (x2 - 2 ) + 2 x, & x < 1 \ ( + 3)x + ( - ), & x 1 cases be differentiable at all x R. Then 34( + ) is equal to

  1. 48
  2. 84
  3. 36
  4. 24
Ques. 5JEE Main 2026, 24 January (Evening Shift)

Let [t] denote the greatest integer less than or equal to t. If the function f(x) = cases b2 ( 2 [ 2( x + x) x ] ), & x < 0 \ x - 12 2xx3, & x > 0 \ a, & x = 0 cases is continuous at x = 0, then a2 + b2 is equal to :

  1. 12
  2. 58
  3. 34
  4. 916
Ques. 6JEE Main 2026, 23 January (Morning Shift)

Let f(x) = cases ax2 + 2ax + 34x2 + 4x - 3 & , x - 32, 12 \ b & , x = - 32, 12 cases be continuous at x = - 32. If f f(x) = 75, then x is equal to:

  1. 1.4
  2. 2
  3. 1
  4. 0
Ques. 7JEE Main 2026, 23 January (Evening Shift)

If f(x) = cases a|x| + x2 - 2( |x|)( |x|)x & , x 0 \ b & , x = 0 cases is continuous at x = 0, then a + b is equal to :

  1. 1
  2. 2
  3. 0
  4. 4
Ques. 8JEE Main 2026, 22 January (Evening Shift)

Let [ ] denote the greatest integer function, and let f(x) = \ 2x, x2 \. Let S = \x (-2, 2) : the function g(x) = |x| [x2 ] is discontinuous at x\. Then x S f(x) equals

  1. 2 - 2
  2. 2 6 - 3 2
  3. 1 - 2
  4. 6 - 2 2
Ques. 9JEE Main 2025, 7 April (Morning Shift)

The number of points of discontinuity of the function f(x) = [ x22 ] - [ x], x [0, 4], where [ ] denotes the greatest integer function, is .

Ques. 10JEE Main 2025, 7 April (Evening Shift)

If the function f(x) = ( x) - ( x) x - x is continuous at x = 0, then f(0) is equal to .

Ques. 11JEE Main 2025, 4 April (Morning Shift)

Let m and n be the number of points at which the function f(x) = \x, x3, x5, , x21 \, x R, is not differentiable and not continuous, respectively. Then m + n is equal to .

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