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Continuity and Differentiability

JEE Main 2026 (Online) 28th January Evening ShiftMCQHard📈 Topic in 34% papers+4−1
Ques. 1JEE Main 2026, 28 January (Evening Shift)

Let f(x) = 0 ( x - x ( 2 ) (x - 1)1 + x ( 2 )(x - 1) ), x R. Consider the following two statements : (I) f(x) is discontinuous at x = 1. (II) f(x) is continuous at x = -1. Then,

  1. Neither (I) nor (II) is True
  2. Only (II) is True
  3. Only (I) is True
  4. Both (I) and (II) are True

Answer

(1) Neither (I) nor (II) is True

Solution

Let n = 1 , so x2/ = (x2)n.

For |x| < 1, (x2)n 0, so f(x) = x.

For |x| > 1, dividing by (x2)n gives f(x) = - (x - 1)x - 1.

For |x| = 1, (x2)n = 1, so f(x) = x - (x - 1)x.

At x = 1: f(1) = = -1

LHL = x 1- x = -1; RHL = x 1+ - (x - 1)x - 1 = -1

so f is continuous at x = 1, and (I) is false.

At x = -1: RHL = x -1+ x = -1

LHL = x -1- - (x - 1)x - 1 = - (-2)-2 = - 22 -1

so f is discontinuous at x = -1, and (II) is false.

Answer: (1)

Keep practising — Continuity and Differentiability

Ques. 2JEE Main 2026, 24 January (Morning Shift)

Let , R be such that the function f(x) = cases 2 (x2 - 2 ) + 2 x, & x < 1 \ ( + 3)x + ( - ), & x 1 cases be differentiable at all x R. Then 34( + ) is equal to

  1. 48
  2. 84
  3. 36
  4. 24
Ques. 3JEE Main 2026, 24 January (Evening Shift)

Let [t] denote the greatest integer less than or equal to t. If the function f(x) = cases b2 ( 2 [ 2( x + x) x ] ), & x < 0 \ x - 12 2xx3, & x > 0 \ a, & x = 0 cases is continuous at x = 0, then a2 + b2 is equal to :

  1. 12
  2. 58
  3. 34
  4. 916
Ques. 4JEE Main 2026, 23 January (Morning Shift)

Let f(x) = cases ax2 + 2ax + 34x2 + 4x - 3 & , x - 32, 12 \ b & , x = - 32, 12 cases be continuous at x = - 32. If f f(x) = 75, then x is equal to:

  1. 1.4
  2. 2
  3. 1
  4. 0
Ques. 5JEE Main 2026, 23 January (Evening Shift)

If f(x) = cases a|x| + x2 - 2( |x|)( |x|)x & , x 0 \ b & , x = 0 cases is continuous at x = 0, then a + b is equal to :

  1. 1
  2. 2
  3. 0
  4. 4
Ques. 6JEE Main 2026, 22 January (Evening Shift)

Let [ ] denote the greatest integer function, and let f(x) = \ 2x, x2 \. Let S = \x (-2, 2) : the function g(x) = |x| [x2 ] is discontinuous at x\. Then x S f(x) equals

  1. 2 - 2
  2. 2 6 - 3 2
  3. 1 - 2
  4. 6 - 2 2
Ques. 7JEE Main 2025, 7 April (Morning Shift)

The number of points of discontinuity of the function f(x) = [ x22 ] - [ x], x [0, 4], where [ ] denotes the greatest integer function, is .

Ques. 8JEE Main 2025, 7 April (Evening Shift)

If the function f(x) = ( x) - ( x) x - x is continuous at x = 0, then f(0) is equal to .

Ques. 9JEE Main 2025, 4 April (Morning Shift)

Let m and n be the number of points at which the function f(x) = \x, x3, x5, , x21 \, x R, is not differentiable and not continuous, respectively. Then m + n is equal to .

Ques. 10JEE Main 2025, 3 April (Morning Shift)

Let f(x) = cases (1 + ax)1/x, & x < 0 \ 1 + b, & x = 0 \ (x+4)1/2 - 2(x+c)1/3 - 2, & x > 0 cases be continuous at x = 0. Then ea bc is equal to:

  1. 64
  2. 48
  3. 36
  4. 72
Ques. 11JEE Main 2025, 29 January (Evening Shift)

Let the function f(x)= (x2-1 ) |x2-ax+2 |+ |x| be not differentiable at the two points x= =2 and x= . Then the distance of the point ( , ) from the line 12x+5y+10=0 is equal to :

  1. 5
  2. 2
  3. 4
  4. 3

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