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Continuity and Differentiability

JEE Main 2025 (Online) 7th April Morning ShiftNumericalMedium📈 Topic in 34% papers+4
Ques. 1JEE Main 2025, 7 April (Morning Shift)

The number of points of discontinuity of the function f(x) = [ x22 ] - [ x], x [0, 4], where [ ] denotes the greatest integer function, is .

Answer

8

Solution

[ x22 ] jumps where x22 = 1, 2, , 8, i.e. x = 2, 2, 6, 2 2, 10, 2 3, 14, 4

[ x] jumps where x = 1, 2, i.e. x = 1, 4

At x = 4 (right end point, only the left-hand limit matters):

x 4- f(x) = 7 - 1 = 6 and f(4) = 8 - 2 = 6 f is continuous at x = 4.

At x = 0: f(x) = 0 for 0 x < 1 continuous.

At each of x = 1, 2, 2, 6, 2 2, 10, 2 3, 14 only one of the two terms jumps f is discontinuous there.

number of points of discontinuity = 8

Answer: 8

Keep practising — Continuity and Differentiability

Ques. 2JEE Main 2025, 7 April (Evening Shift)

If the function f(x) = ( x) - ( x) x - x is continuous at x = 0, then f(0) is equal to .

Ques. 3JEE Main 2025, 4 April (Morning Shift)

Let m and n be the number of points at which the function f(x) = \x, x3, x5, , x21 \, x R, is not differentiable and not continuous, respectively. Then m + n is equal to .

Ques. 4JEE Main 2025, 3 April (Morning Shift)

Let f(x) = cases (1 + ax)1/x, & x < 0 \ 1 + b, & x = 0 \ (x+4)1/2 - 2(x+c)1/3 - 2, & x > 0 cases be continuous at x = 0. Then ea bc is equal to:

  1. 64
  2. 48
  3. 36
  4. 72
Ques. 5JEE Main 2025, 29 January (Evening Shift)

Let the function f(x)= (x2-1 ) |x2-ax+2 |+ |x| be not differentiable at the two points x= =2 and x= . Then the distance of the point ( , ) from the line 12x+5y+10=0 is equal to :

  1. 5
  2. 2
  3. 4
  4. 3
Ques. 6JEE Main 2025, 28 January (Morning Shift)

Let f(x) = cases 3x, & x < 0 \ \1 + x + [x], x + 2[x]\, & 0 x 2 \ 5, & x > 2 cases where [.] denotes greatest integer function. If and are the number of points, where f is not continuous and is not differentiable, respectively, then + equals .

Ques. 7JEE Main 2025, 24 January (Evening Shift)

Let [x] denote the greatest integer function, and let m and n respectively be the numbers of the points, where the function f(x)=[x]+|x-2|, -2<x<3, is not continuous and not differentiable. Then m+n is equal to :

  1. 6
  2. 9
  3. 8
  4. 7
Ques. 8JEE Main 2025, 23 January (Morning Shift)

If the function f(x)= cases 2x \ (k1+1)x+ (k2-1)x \, & x<0\\[2mm] 4, & x=0\\[2mm] 2x e ( 2+k1x2+k2x ), & x>0 cases is continuous at x=0, then k12+k22 is equal to :

  1. 5
  2. 10
  3. 20
  4. 8
Ques. 9JEE Main 2024, 9 April (Morning Shift)

Let f(x) = ax3 + bx2 + cx + 41 be such that f(1) = 40, f'(1) = 2 and f''(1) = 4. Then a2 + b2 + c2 is equal to:

  1. 54
  2. 51
  3. 73
  4. 62
Ques. 10JEE Main 2024, 9 April (Morning Shift)

Let f : (0, ) R be a function given by f(x) = cases ( 87 ) 8x 7x, & 0 < x < 2 \ a - 8, & x = 2 \ (1 + | x|) ba| x|, & 2 < x < cases where a, b Z. If f is continuous at x = 2, then a2 + b2 is equal to .

Ques. 11JEE Main 2024, 9 April (Evening Shift)

If e y = 3 -1x, then (1 - x2)y'' - xy' at x = 12 is equal to

  1. 9e /2
  2. 9e /6
  3. 3e /2
  4. 3e /6

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