A small uncharged conducting sphere is placed in contact with an identical sphere but having 4 10-8 C charge and then removed to a distance such that the force of repulsion between them is 9 10-3 N. The distance between them is (Take 14 0 as 9 109 in SI units)
- 1 cm
- 2 cm
- 4 cm
- 3 cm
Answer
(2) 2 cm
Solution
Identical conducting spheres share charge equally: q'= 4 10-82=2 10-8 C
[figure]
F= 14 0 q'2r2 r2= 9 109 4 10-169 10-3=4 10-4 m2
r=2 10-2 m=2 cm
Answer: (2)