A plane electromagnetic wave of frequency 20 MHz travels in free space along the +x direction. At a particular point in space and time, the electric field vector of the wave is Ey=9.3 V m-1. Then, the magnetic field vector of the wave at that point is
- Bz=1.55 10-8 T
- Bz=6.2 10-8 T
- Bz=3.1 10-8 T
- Bz=9.3 10-8 T
Answer
(3) Bz=3.1 10-8 T
Solution
In free space B= Ec= 9.33 108=3.1 10-8 T.
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E B must point along the travel direction +x: j k= i, so B is along +z.
Bz=3.1 10-8 T
Answer: (3)