A certain gas takes three times as long to effuse out as helium. Its molecular mass will be
- 27 u
- 36 u
- 64 u
- 9 u
Answer
(2) 36 u
Solution
By Graham's law, the rate of effusion r 1 M, and for the same volume the time taken t 1r M, so
tgastHe = MMHe
3 = M4
M = 9 4 = 36 u
Answer: (2)