A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75\% of octahedral voids. The formula of the compound is :
- C3A4
- C4A3
- C2A3
- C3A
Answer
(1) C3A4
Solution
In a close packed lattice, the number of octahedral voids equals the number of anions.
Let the number of anions A = N; then there are N octahedral voids, and the cations occupy 75% of them, so
C = 75100 N = 34N
C : A = 34N : N = 3 : 4
∴ The formula is C3A4.
Answer: (1)