An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is :
(4) 34 288 pm
In a bcc unit cell, the atoms touch each other along the body diagonal.
∴ Body diagonal = 4r
⇒ 3 a = 4r
⇒ r = 34 a
= 34 288 pm
Answer: (4)
A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75\% of octahedral voids. The formula of the compound is :
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Which is the incorrect statement?
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If a is the length of the side of a cube, the distance between the body centered atom and one corner atom in the cube will be