The products A and B formed in the following reaction scheme are respectively [figure]
- [figure]
- [figure]
- [figure]
- [figure]
Answer
(2) [figure]
Solution
[figure]
∵ Sn/HCl reduces –NO2 to –NH2 ⇒ A = aniline
A NaNO2, HCl, 273-278 K benzenediazonium chloride (diazotisation)
[figure]
∵ –OH is o/p-directing; the bulky ArN2 couples at the less hindered para position ⇒ B = p-hydroxyazobenzene (orange dye)
(A): –N=N– ortho to –OH ⇒ (A) is wrong
(C), (D): no –N=N– group ⇒ (C), (D) are wrong
Answer: (2)