The motion of an airplane is represented by velocity-time graph as shown below. The distance covered by airplane in the first 30.5 second is km . [figure]
(1) 12
Distance = area under the v–t graph: trapezium (0–2 s) + rectangle (2–30.5 s).
[figure]
s1= 12(200+400) 2=600 m
s2=400 28.5=11400 m
s=12000 m=12 km
Answer: (1)
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