A wire of resistance R and radius r is stretched till its radius became r/2. If new resistance of the stretched wire is x R, then value of x is .
Answer
16
Solution
R = l 2; volume constant 2l = ( r2 )2l' l' = 4l
R' = (4l) 2/4 = 16 l 2 = 16R
x = 16
Answer: 16