X2(g) + Y2(g) 2Z(g) X2(g) and Y2(g) are added to a 1 L flask and it is found that the system attains the above equilibrium at T(K) with the number of moles of X2(g), Y2(g) and Z(g) being 3, 3 and 9 mol respectively (equilibrium moles). Under this condition of equilibrium, 10 mol of Z(g) is added to the flask and the temperature is maintained at T(K). Then the number of moles of Z(g) in the flask when the new equilibrium is established is . (Nearest integer)
Answer
15
Solution
The volume is 1 L, so moles = concentrations and
Kc = [Z]2[X2][Y2] = 923 3 = 9
After adding 10 mol Z, Qc = 1923 3 > Kc, so the reaction moves backward.
Let a mol of X2 be formed; then X2 = Y2 = 3 + a and Z = 19 - 2a, so
(19 - 2a)2(3 + a)2 = 9
19 - 2a = 3(3 + a)
5a = 10 a = 2
Moles of Z = 19 - 2(2) = 15
Answer: 15