The solubility product of AgI at 25 C is 1.0 10-16 mol2 L-2. The solubility of AgI in 10-4 N solution of KI at 25 C is approximately (in mol L-1)
- 1.0 10-16
- 1.0 10-12
- 1.0 10-10
- 1.0 10-8
Answer
(2) 1.0 10-12
Solution
For KI normality equals molarity, so the common ion gives [I-] = 10-4 mol L-1.
Let the solubility of AgI be s; then [Ag+] = s and [I-] = s + 10-4 10-4, since s is very small.
Ksp = [Ag+][I-]
1.0 10-16 = s 10-4
s = 1.0 10-12 mol L-1
Answer: (2)