Let f : R R be a function such that f(x)+3f ( 2-x )= x, x R. Let the maximum value of f on R be . If the area of the region bounded by the curves g(x)=x2 and h(x)= x3, >0, is 2, then 30 3 is equal to .
Answer
16
Solution
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Given f(x) + 3f ( 2 - x ) = x …(i); replacing x by 2 - x gives f ( 2 - x ) + 3f(x) = x …(ii)
Then 3 (ii) − (i): 8f(x) = 3 x - x, so f(x) = 3 x - x8 and
= 32 + 128 = 108 2 = 1064 = 532
x2 = x3 gives x = 0 or x = 1 , and for 0 < x < 1 , x2 > x3, so
Area = 01/ (x2 - x3 )dx = 13 3 - 14 3 = 112 3
112 3 = 532 3 = 3260 = 815
30 3 = 16
Answer: 16