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Application of Integrals

JEE Main 2026 (Online) 4th April Evening ShiftMCQMedium📈 Topic in 71% papers+4−1
Ques. 1JEE Main 2026, 4 April (Evening Shift)

The area of the region bounded by the curves x+3y2=0 and x+4y2=1 is equal to :

  1. 13
  2. 23
  3. 43
  4. 53

Answer

(3) 43

Solution

[figure]

Intersection: -3y2=1-4y2 y2=1 y= 1, points (-3, 1)

For -1 y 1: left boundary x=-3y2, right boundary x=1-4y2

Area = -11 [ (1-4y2 )- (-3y2 ) ]dy

= -11 (1-y2 )dy=2 [y- y33 ]01=2 23= 43

Answer: (3)

Keep practising — Application of Integrals

Ques. 2JEE Main 2026, 2 April (Evening Shift)

If the area of the region bounded by 16x2-9y2=144 and 8x-3y=24 is A, then 3 (A+6 e(3) ) is equal to .

Ques. 3JEE Main 2026, 28 January (Morning Shift)

The area of the region R = \(x, y) : xy 8, 1 y x2, x 0\ is

  1. 23(20 e(2) + 9)
  2. 13(40 e(2) + 27)
  3. 13(49 e(2) - 15)
  4. 23(24 e(2) - 7)
Ques. 4JEE Main 2026, 28 January (Evening Shift)

Let P1 : y = 4x2 and P2 : y = x2 + 27 be two parabolas. If the area of the bounded region enclosed between P1 and P2 is six times the area of the bounded region enclosed between the line y = x, > 0 and P1, then is equal to :

  1. 12
  2. 15
  3. 8
  4. 6
Ques. 5JEE Main 2026, 24 January (Morning Shift)

Let A1 be the bounded area enclosed by the curves y = x2 + 2, x + y = 8 and y-axis that lies in the first quadrant. Let A2 be the bounded area enclosed by the curves y = x2 + 2, y2 = x, x = 2, and y-axis that lies in the first quadrant. Then A1 - A2 is equal to

  1. 23(2 2 + 1)
  2. 23(3 2 + 1)
  3. 23( 2 + 1)
  4. 23(4 2 + 1)
Ques. 6JEE Main 2026, 24 January (Evening Shift)

Let f( ) denote the area of the region in the first quadrant bounded by x = 0, x = 1, y2 = x and y = | x - 5| - |1 - x| + x2. Then (f(0) + f(1)) is equal to

  1. 12
  2. 14
  3. 9
  4. 7
Ques. 7JEE Main 2026, 23 January (Morning Shift)

Let the area of the region bounded by the curve y = \ x, x\, lines x = 0, x = 3 2, and the x-axis be A. Then, A + A2 is equal to .

Ques. 8JEE Main 2026, 23 January (Evening Shift)

The area of the region enclosed between the circles x2 + y2 = 4 and x2 + (y - 2)2 = 4 is:

  1. 23(4 - 3 3)
  2. 43(2 - 3)
  3. 43(2 - 3 3)
  4. 23(2 - 3 3)
Ques. 9JEE Main 2026, 22 January (Morning Shift)

Let the line x = -1 divide the area of the region \(x, y) : 1 + x2 y 3 - x \ in the ratio m : n, (m, n) = 1. Then m + n is equal to

  1. 27
  2. 28
  3. 25
  4. 26
Ques. 10JEE Main 2026, 22 January (Evening Shift)

The area of the region A = \(x, y) : 4x2 + y2 8 and y2 4x\ is:

  1. + 23
  2. 2 + 2
  3. + 4
  4. 2 + 13
Ques. 11JEE Main 2026, 21 January (Morning Shift)

The area of the region, inside the ellipse x2 + 4y2 = 4 and outside the region bounded by the curves y = |x| - 1 and y = 1 - |x|, is :

  1. 2 - 1
  2. 3( - 1)
  3. 2( - 1)
  4. 2 - 12

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