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Application of Integrals

JEE Main 2026 (Online) 28th January Evening ShiftMCQMedium📈 Topic in 72% papers+4−1
Ques. 1JEE Main 2026, 28 January (Evening Shift)

Let P1 : y = 4x2 and P2 : y = x2 + 27 be two parabolas. If the area of the bounded region enclosed between P1 and P2 is six times the area of the bounded region enclosed between the line y = x, > 0 and P1, then is equal to :

  1. 12
  2. 15
  3. 8
  4. 6

Answer

(1) 12

Solution

P1 P2: 4x2 = x2 + 27 x = 3

A1 = -33 (x2 + 27 - 4x2) dx = 2 03 (27 - 3x2) dx

= 2[27x - x3]03 = 2(81 - 27) = 108

Line and P1: x = 4x2 x = 0, 4

A2 = 0 /4 ( x - 4x2) dx = 2 216 - 43 364

= 332 - 348 = 396

Given A1 = 6A2:

108 = 6 396 3 = 1728

= 12

Answer: (1)

Keep practising — Application of Integrals

Ques. 2JEE Main 2026, 24 January (Morning Shift)

Let A1 be the bounded area enclosed by the curves y = x2 + 2, x + y = 8 and y-axis that lies in the first quadrant. Let A2 be the bounded area enclosed by the curves y = x2 + 2, y2 = x, x = 2, and y-axis that lies in the first quadrant. Then A1 - A2 is equal to

  1. 23(2 2 + 1)
  2. 23(3 2 + 1)
  3. 23( 2 + 1)
  4. 23(4 2 + 1)
Ques. 3JEE Main 2026, 24 January (Evening Shift)

Let f( ) denote the area of the region in the first quadrant bounded by x = 0, x = 1, y2 = x and y = | x - 5| - |1 - x| + x2. Then (f(0) + f(1)) is equal to

  1. 12
  2. 14
  3. 9
  4. 7
Ques. 4JEE Main 2026, 23 January (Morning Shift)

Let the area of the region bounded by the curve y = \ x, x\, lines x = 0, x = 3 2, and the x-axis be A. Then, A + A2 is equal to .

Ques. 5JEE Main 2026, 23 January (Evening Shift)

The area of the region enclosed between the circles x2 + y2 = 4 and x2 + (y - 2)2 = 4 is:

  1. 23(4 - 3 3)
  2. 43(2 - 3)
  3. 43(2 - 3 3)
  4. 23(2 - 3 3)
Ques. 6JEE Main 2026, 22 January (Morning Shift)

Let the line x = -1 divide the area of the region \(x, y) : 1 + x2 y 3 - x \ in the ratio m : n, (m, n) = 1. Then m + n is equal to

  1. 27
  2. 28
  3. 25
  4. 26
Ques. 7JEE Main 2026, 22 January (Evening Shift)

The area of the region A = \(x, y) : 4x2 + y2 8 and y2 4x\ is:

  1. + 23
  2. 2 + 2
  3. + 4
  4. 2 + 13
Ques. 8JEE Main 2026, 21 January (Morning Shift)

The area of the region, inside the ellipse x2 + 4y2 = 4 and outside the region bounded by the curves y = |x| - 1 and y = 1 - |x|, is :

  1. 2 - 1
  2. 3( - 1)
  3. 2( - 1)
  4. 2 - 12
Ques. 9JEE Main 2026, 21 January (Evening Shift)

If the area of the region \(x, y) : 1 - 2x y 4 - x2, x 0, y 0\ is , , N, ( , ) = 1, then the value of ( + ) is:

  1. 73
  2. 85
  3. 67
  4. 91
Ques. 10JEE Main 2025, 8 April (Evening Shift)

Let the area of the bounded region \(x, y) : 0 9x y2, y 3x - 6 \ be A. Then 6A is equal to .

Ques. 11JEE Main 2025, 7 April (Morning Shift)

If the area of the region bounded by the curves y = 4 - x24 and y = x-42 is equal to , then 6 equals

  1. 210
  2. 250
  3. 240
  4. 220

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