An electron of mass m with an initial velocity v = v0 i (v0 > 0) enters an electric field E = -E0 i (E0 = constant > 0) at t = 0. If 0 is its de-Broglie wavelength initially, then its de-Broglie wavelength at time t is
- 0 (1 + eE0mv0t )
- 0 (1 + eE0mv0t )
- 0t
- 0
Answer
(1) 0 (1 + eE0mv0t )
Solution
The force on the electron is F = -e E = eE0 i, along its velocity, so it speeds up:
v = v0 + eE0mt
Since = hmv and 0 = hmv0,
= hm (v0 + eE0mt ) = 0 (1 + eE0mv0t )
Answer: (1)