A ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle ( ) of thread deflection in the extreme position will be :
- -1 ( 12 )
- 2 -1 ( 12 )
- 2 -1 ( 1 5 )
- -1 ( 2 )
Answer
(2) 2 -1 ( 12 )
Solution
[figure]
Extreme position (v=0): only tangential acceleration =g
Lowest point (no tangential force): a= v2 , where energy gives 12mv2=mg (1- )
v2 =2g(1- )
Equal accelerations: g =2g(1- )
2 2 2=4 2 2
2= 12 =2 -1 ( 12 )
Answer: (2)