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Chemical Bonding and Molecular Structure

JEE Main 2026 (Online) 4th April Evening ShiftMCQEasy📈 Topic in 29% papers+4−1
Ques. 1JEE Main 2026, 4 April (Evening Shift)

Which of the following pictorial diagrams most correctly represents the * ( antibonding) molecular orbital between two atoms if the internuclear axis is taken to be in the z-direction ( z-axis) ?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(3) [figure]

Solution

∵ The internuclear axis is z, π-type MOs are formed by sideways overlap of px (or py) orbitals, which lie perpendicular to the axis. Lobes pointing along the axis, as in (4), belong to σ-type (end-on) overlap of pz orbitals.

In-phase combination (same shading on the same side of the axis) ⇒ π bonding MO: electron density above and below the axis, spread over both nuclei — this is shown in (1); (2) also shows the two p orbitals in phase.

Out-of-phase combination ⇒ π antibonding MO: the upper lobe of one atom has the same shading as the lower lobe of the other atom (like-shaded lobes lie diagonally opposite), the lobes bend away from each other and a nodal plane lies between the two nuclei.

∴ Option (3) represents the * MO.

Answer: (3)

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Ques. 2JEE Main 2026, 2 April (Morning Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true
Ques. 3JEE Main 2026, 2 April (Evening Shift)

SF4 is isostructural with : Choose the correct answer from the options given below :

  1. C Only
  2. C and E Only
  3. A and D Only
  4. B and E Only
Ques. 4JEE Main 2026, 28 January (Morning Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Statement I is true but Statement II is false
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are true
Ques. 5JEE Main 2026, 28 January (Evening Shift)

Match List-I with List-II according to shape. Choose the correct answer from the options given below :

  1. A-II, B-III, C-I, D-IV
  2. A-III, B-II, C-IV, D-I
  3. A-II, B-III, C-IV, D-I
  4. A-II, B-I, C-III, D-IV
Ques. 6JEE Main 2026, 24 January (Morning Shift)

Given below are statements about some molecules/ions. Identify the CORRECT statements. Choose the correct answer from the options given below:

  1. B & C Only
  2. B, C & D Only
  3. A, C & D Only
  4. A, B, C, D & E
Ques. 7JEE Main 2026, 24 January (Morning Shift)

Among the following, the CORRECT combinations are Choose the correct answer from the options given below:

  1. B, C and D Only
  2. A, B, C and D
  3. A, B and C Only
  4. A and B Only
Ques. 8JEE Main 2026, 24 January (Evening Shift)

Pair of species among the following having same bond order as well as paramagnetic character will be-

  1. O2-, N2+
  2. O2+, N22-
  3. O2-, N2-
  4. O2+, N2-
Ques. 9JEE Main 2026, 23 January (Morning Shift)

Identify the molecule (X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNO3, H2SO4, NF3 and O3. Choose the correct bond angle made by the central atom of the molecule (X).

  1. 107
  2. 102
  3. 120
  4. 116
Ques. 10JEE Main 2026, 23 January (Evening Shift)

Which statements are NOT TRUE about XeO2F2? Choose the correct answer from the options given below :

  1. B, D and E Only
  2. B and D Only
  3. B, C and E Only
  4. A and D Only
Ques. 11JEE Main 2026, 22 January (Morning Shift)

Two p-block elements X and Y form fluorides of the type EF3. The fluoride compound XF3 is a Lewis acid and YF3 is a Lewis base. The hybridizations of the central atoms of XF3 and YF3 respectively are

  1. sp2 and sp3
  2. Both sp3
  3. Both sp2
  4. sp3 and sp2

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