The de-Broglie wavelength of an electron is the same as that of a photon. If velocity of electron is 25\% of the velocity of light, then the ratio of K.E. of electron and K.E. of photon will be:
- 14
- 81
- 18
- 11
Answer
(3) 18
Solution
Same same momentum p= h
Electron: Ke= 12mv2= 12pv
Photon: Ep=pc
KeEp= v2c= 0.25c2c= 18
Answer: (3)