An electron in the ground state of the hydrogen atom has the orbital radius of 5.3 10-11 m while that for the electron in third excited state is 8.48 10-10 m. The ratio of the de Broglie wavelengths of electron in the ground state to that in the excited state is
- 4
- 3
- 9
- 16
Answer
(1) 4
Solution
Bohr + de Broglie: 2 r=n , so = 2 rn. Third excited state n=4 (r4=16r1 matches the given radius).
[figure]
1=2 r1, 4= 2 (16r1)4=4 1
The wavelengths differ by a factor 4
Answer: (1)