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Aldehydes, Ketones and Carboxylic Acids

JEE Main 2026 (Online) 23rd January Morning ShiftMCQMedium📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2026, 23 January (Morning Shift)

[figure] The correct sequence of reagents for the above conversion of X to Y is :

  1. (i) NaOH(aq), (ii) Jones reagent, (iii) H3O+
  2. (i) NaOEt, (ii) B2H6/H2O2, (iii) Jones reagent
  3. (i) Jones reagent, (ii) NaOEt, (iii) Hot KMnO4/KOH
  4. (i) B2H6/H2O2, (ii) NaOEt, (iii) Jones reagent

Answer

(2) (i) NaOEt, (ii) B2H6/H2O2, (iii) Jones reagent

Solution

X is 1-bromo-1-phenylethane; in Y the oxygen function is on the terminal carbon, so an anti-Markovnikov route is needed:

[figure]

(i) NaOEt (strong base): dehydrobromination gives styrene, C6H5CH=CH2

(ii) B2H6/H2O2 (hydroboration–oxidation): anti-Markovnikov addition of water gives 2-phenylethanol, C6H5CH2CH2OH

(iii) Jones reagent (CrO3/H2SO4): oxidises the 1° alcohol to phenylacetic acid, C6H5CH2COOH (Y)

Option (1) puts –OH on the benzylic carbon (Jones reagent then gives a ketone), in option (3) Jones reagent cannot act on the alkyl halide, and in option (4) B2H6 cannot act on an alkyl halide.

Answer: (2)

Keep practising — Aldehydes, Ketones and Carboxylic Acids

Ques. 2JEE Main 2026, 23 January (Evening Shift)

Which of the following statements are TRUE about Haloform reaction? Choose the correct answer from the options given below :

  1. A, B & C Only
  2. A, C & E Only
  3. B, D & E Only
  4. A & C Only
Ques. 3JEE Main 2026, 23 January (Evening Shift)

Iodoform test can differentiate between Choose the correct answer from the options given below :

  1. A, B & E Only
  2. A & D Only
  3. A & E Only
  4. B, C & E Only
Ques. 4JEE Main 2026, 23 January (Evening Shift)

Consider the following reaction of benzene. [figure] In compound (Q), the percentage of oxygen is %. (Nearest integer)

Ques. 5JEE Main 2026, 22 January (Morning Shift)

Match the LIST-I with LIST-II Choose the correct answer from the options given below :

  1. A-IV, B-III, C-II, D-I
  2. A-III, B-I, C-IV, D-II
  3. A-II, B-I, C-IV, D-III
  4. A-III, B-IV, C-I, D-II
Ques. 6JEE Main 2026, 22 January (Evening Shift)

The compound A, C8H8O2 reacts with acetophenone to form a single product via cross-Aldol condensation. The compound A on reaction with conc. NaOH forms a substituted benzyl alcohol as one of the two products. The compound A is :

  1. 2-hydroxy acetophenone
  2. 4-hydroxy benzaldehyde
  3. 4-methyl benzoic acid
  4. 4-methoxy benzaldehyde
Ques. 7JEE Main 2026, 21 January (Morning Shift)

An organic compound "P" of molecular formula C6H12O3 gives positive iodoform test but negative Tollens' test. When "P" is treated with dilute acid, it produces "Q". "Q" gives positive Tollens' test and also iodoform test. The structure of "P" is :

  1. H- O \|C-CH2-CH2- OCH3 |CH-OCH3
  2. CH3- O \|C- OCH3 |CH- OCH3 |CH2
  3. CH3- O \|C-CH2- OCH3 |CH-OCH3
  4. CH3- O \|C- OCH3 | OCH3 |C-CH3
Ques. 8JEE Main 2026, 21 January (Evening Shift)

Match List - I with List - II. Choose the correct answer from the options given below :

  1. A-II, B-III, C-IV, D-I
  2. A-IV, B-III, C-I, D-II
  3. A-IV, B-I, C-II, D-III
  4. A-II, B-IV, C-I, D-III
Ques. 9JEE Main 2025, 8 April (Evening Shift)

A [(ii) H3O+](i) NaOH B [(ii) H2SO4, ](i) EtOH C 'A' shows positive Lassaigne's test for N and its molar mass is 121. 'B' gives effervescence with aq NaHCO3. 'C' gives fruity smell. Identify A, B and C from the following.

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 10JEE Main 2025, 8 April (Evening Shift)

When [figure] undergoes intramolecular aldol condensation, the major product formed is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 11JEE Main 2025, 7 April (Morning Shift)

Which of the following compounds is least likely to give effervescence of CO2 in presence of aq. NaHCO3?

  1. Ph- NH3 Cl
  2. [figure]
  3. [figure]
  4. [figure]

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