The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
- 0.707
- zero
- 0.5
Answer
(4) 0.5
Solution
For SHM, x = A t, so
v = A t = A ( t + 2 )
a = -A 2 t = A 2 ( t + )
∴ The phase difference between v and a is - 2 = 2 = 0.5 .
Answer: (4)